When y is not solved explicitly, differentiate both sides w.r.t. \(x\), treating \(y\) as \(y(x)\):
Example: \(x^2 + y^2 = 25\) (circle)
\(2x + 2y dy/dx = 0 \rightarrow dy/dx = -x/y\)
At point \((3,4)\): slope = -3/4
Find slope → write equation of tangent line.
Example: \(x^3 + y^2 = 9xy\) at \((2,1)\)
\(3x^2 + 3y^2 dy/dx = 9y + 9x dy/dx\)
\(dy/dx = (9y - 3x^2)/(3y^2 - 9x)\)
At \((2,1)\): slope = \((9-12)/(3-18) = (-3)/(-15) = 1/5\)